How many grams of ZnCl2 will be produced from 48 grams of zinc and 30 grams of HCL
This is a limiting reagent problem. Here is a posting I did for limiting reagent problems. Just follow the steps.
To determine the number of grams of ZnCl2 produced, we need to determine the limiting reactant first. The limiting reactant is the reactant that will be completely consumed and determines the maximum amount of product that can be formed.
First, we need to convert the given masses of zinc (Zn) and hydrochloric acid (HCl) to moles. To do this, we use the molar masses of each element:
Molar mass of Zn = 65.38 g/mol
Molar mass of HCl = 36.46 g/mol
Converting grams to moles:
Moles of Zn = Mass of Zn / Molar mass of Zn
Moles of Zn = 48 g / 65.38 g/mol
Moles of Zn = 0.734 mol
Moles of HCl = Mass of HCl / Molar mass of HCl
Moles of HCl = 30 g / 36.46 g/mol
Moles of HCl = 0.822 mol
Next, we need to determine the stoichiometry of the reaction between zinc and hydrochloric acid. The balanced chemical equation for the reaction is:
Zn + 2HCl -> ZnCl2 + H2
From the balanced equation, we can see that the molar ratio between Zn and ZnCl2 is 1:1.
Since the moles of Zn and ZnCl2 are the same, the limiting reactant is zinc. This means that all the zinc will react, and the amount of ZnCl2 formed will be determined by the amount of zinc.
Finally, we need to convert the moles of Zn to grams of ZnCl2 by multiplying by the molar mass of ZnCl2.
Moles of ZnCl2 = Moles of Zn = 0.734 mol
Mass of ZnCl2 = Moles of ZnCl2 * Molar mass of ZnCl2
Mass of ZnCl2 = 0.734 mol * 136.29 g/mol
Mass of ZnCl2 = 100.12 g
Therefore, 48 grams of zinc and 30 grams of HCl will produce 100.12 grams of ZnCl2.