"Adult tickets are $6, Kids are $3. If the total sales are $585, but only 120 tickets were sold, how many adult tickets were sold?
If this was 130 it would be easy: $3+$6 =$9; $585/$9 = 65 tickets. The problem is the question specifies 120 tickets.
adult tickets ---- x
children tickets -- y
x+y = 120
cost equation:
6x + 3y = 585
or after dividing by 3
2x + y = 195
subtract the two equations:
2x+y = 195
x + y = 120
----------
x = 75
then in x+y = 120
75 + y = 120
y = 45
they sold 75 adults, and 45 children tickets
check:
75(6) + 45(3) = 585 , yeahhhh
To solve this problem, we can set up a system of equations based on the given information. Let's use variables to represent the number of adult tickets and the number of kids' tickets.
Let's say the number of adult tickets is represented by 'A' and the number of kids' tickets is represented by 'K'. We can write the following equations:
1) A + K = 120 (This equation represents the total number of tickets sold)
2) 6A + 3K = 585 (This equation represents the total sales in dollars)
We now have a system of equations to solve.
First, let's solve equation 1) for 'A' in terms of 'K':
A = 120 - K
Next, substitute this expression for 'A' into equation 2):
6(120 - K) + 3K = 585
Now, we can solve for 'K':
720 - 6K + 3K = 585
720 - 3K = 585
-3K = -135
K = 45
Now that we know the number of kids' tickets sold is 45, we can substitute this value back into equation 1) to find 'A':
A + 45 = 120
A = 120 - 45
A = 75
Therefore, 75 adult tickets were sold.