can someone please show me the answer for this problem ?

a tree is situated on level ground from a point 135 feet from the base of the tree the measure of the angle of elevation from the ground to the top of the tree is 43 degrees which is the height of the tree to the nearest foot?

What don't you understand about BobPursley's answer?

http://www.jiskha.com/display.cgi?id=1364232189

To find the height of the tree, we can use trigonometry. Let's refer to the base of the tree as point A and the top of the tree as point B. We are given that the distance between A and the point on the ground where the observation is made is 135 feet. We also know that the angle of elevation from the ground to the top of the tree is 43 degrees.

To solve this problem, we can use the tangent function, which relates the angle of elevation and the opposite side (height of the tree) with the adjacent side (distance from the base of the tree to the observation point).

The tangent of an angle is equal to the ratio of the opposite side to the adjacent side. In this case, the tangent of 43 degrees is equal to the height of the tree divided by the distance of 135 feet.

So, we have the equation:

tan(43 degrees) = height / 135

To find the height of the tree, we can solve for height:

height = tan(43 degrees) * 135

Calculating this expression:
height = tan(43 degrees) * 135
height ≈ 133.70 feet

Therefore, the height of the tree to the nearest foot is approximately 134 feet.