What is the total capacitance of capacitors connected in series, C1=444F, C2=621F
To find the total capacitance of capacitors connected in series, you can use the formula:
1/C_total = 1/C1 + 1/C2 + ...
In this case, you have two capacitors connected in series with capacitance values C1 = 444F and C2 = 621F.
Substituting the values into the formula, we have:
1/C_total = 1/444F + 1/621F
To simplify the equation, we need to find a common denominator for the two fractions, which is 276,924F.
1/C_total = (621F + 444F) / 276,924F
1/C_total = 1065F / 276,924F
Now, we can take the reciprocal of both sides of the equation to solve for C_total:
C_total = 276,924F / 1065F
C_total ≈ 259.93F
Therefore, the total capacitance of the two capacitors connected in series is approximately 259.93F.