What is the bond order of BN-
To determine the bond order of BN-, you need to follow these steps:
Step 1: Write the electron configuration of the atoms involved.
The electron configuration of nitrogen (N) is 1s² 2s² 2p³, and boron (B) is 1s² 2s² 2p¹.
Step 2: Calculate the total number of valence electrons.
Nitrogen has 5 valence electrons (2s² 2p³), and boron has 3 valence electrons (2s² 2p¹). The negative charge on BN- suggests the addition of one extra electron.
Total valence electrons for BN- = 5 + 3 + 1 (extra electron) = 9.
Step 3: Determine the molecular orbital diagram.
The molecular orbital (MO) diagram for BN- would show the combination of the atomic orbitals of boron and nitrogen. You would need to draw the overlapping atomic orbitals and fill them with the available electrons. The molecular orbital diagram would indicate the different bonding and anti-bonding molecular orbitals.
Step 4: Calculate the bond order.
To calculate the bond order, you need to find the difference between the number of bonding electrons and anti-bonding electrons and divide by 2.
Bond order = (number of bonding electrons - number of anti-bonding electrons) / 2
Count the number of electrons in the bonding orbitals and anti-bonding orbitals, and then determine the bond order.
Note: A positive bond order indicates a stable molecule, while a bond order of 0 indicates the molecule is non-existent.
By following these steps, you should be able to determine the bond order of BN-.