Question

in triangle ABC, AB = BC and ABC = 42. find ACB

Answer 1

I will assume that the area of triangle ABC = 42 square units

I don't have enough information.
here is why ....
let each of the equal sides be x
and Ø be the angle between then
area = (1/2)x^2 sinØ
42/sinØ = x^2 ------> 2 unknows, one equation.