a positive test charge of 3.0uC experiences a force of 0.75 N in an electric field. What is the magnitude of the electric field at the location of the test charge?
To find the magnitude of the electric field at the location of the test charge, you can use the following formula:
Electric field (E) = Force (F) / Test charge (q)
Given:
Force (F) = 0.75 N
Test charge (q) = 3.0 uC (micro-Coulombs)
However, before you can use this formula, it's important to note that the unit of the test charge needs to be converted to Coulombs.
1 Coulomb (C) = 1 x 10^(-6) uC
So, converting the charge to Coulombs:
Test charge (q) = 3.0 uC = 3.0 x 10^(-6) C
Now, you can substitute the values into the formula:
Electric field (E) = 0.75 N / 3.0 x 10^(-6) C
Calculating this equation will give you the magnitude of the electric field at the location of the test charge.