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The formula h=48t16t^2 gives the height, h, in feet, of an object projected into the air after t seconds. If an object is propelled upward, at what time(s) will it reach a height of 32 feet above the ground? 
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using this information: if an object is thrown straight up into the air from the height H feet per second then at time tseconds the height of the object is 16.1t^2 +Vt+ H feet. This formula uses only gravitational force, ignoring 
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using this information: if an object is thrown straight up into the air from the height H feet per second then at time tseconds the height of the object is 16.1t^2 +Vt+ H feet. This formula uses only gravitational force, ignoring 
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In physics, one learns that the height of an object thrown upward from an initial height of h0 feet with an initial velocity of v0 (in feet per second) is given by the formula h(t)=−16t^2+v0t+h0 feet where t is the amount of 
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A plane is flying horizontally at a height of 500 m and a constant speed of 429 km/h when an object is projected vertically downward at an initial speed of 35.0 m/s. If air resistance is neglected, the average vertical component 
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THe function h(t)=16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet per second, if there is no air friction and t is the