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Math : Statistics
The formula h=vt−16t^2 gives the height h, in feet, of an object projected into the air with an initial vertical velocity v, in feet per second, after t seconds. If an object is projected upward with an initial velocity of 112
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The formula h=48t16t^2 gives the height, h, in feet, of an object projected into the air after t seconds. If an object is propelled upward, at what time(s) will it reach a height of 32 feet above the ground?
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Please help me solve this: If an object is projected upward with an initial velocity of 112 feet per second from a height h of 128 feet, then its height t seconds after it is projected is defined by the equation h=16t^2 + 112t +
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Near the surface of the earth, the acceleration of a falling body due to gravity is 32 feet per second per second, provided that air resistance is neglected. If an object is thrown upward from and initial height of 3000 feet with
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An object is projected vertically upwards and returns to the point of projection 12s later. Ignore air resistance and determine the velocity with which it was projected?
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using this information: if an object is thrown straight up into the air from the height H feet per second then at time tseconds the height of the object is 16.1t^2 +Vt+ H feet. This formula uses only gravitational force, ignoring
asked by deana on February 10, 2012 
math
using this information: if an object is thrown straight up into the air from the height H feet per second then at time tseconds the height of the object is 16.1t^2 +Vt+ H feet. This formula uses only gravitational force, ignoring
asked by deana on February 10, 2012 
math. can someone explain this!
using this information: if an object is thrown straight up into the air from the height H feet per second then at time tseconds the height of the object is 16.1t^2 +Vt+ H feet. This formula uses only gravitational force, ignoring
asked by deana on February 10, 2012 
Math
In physics, one learns that the height of an object thrown upward from an initial height of h0 feet with an initial velocity of v0 (in feet per second) is given by the formula h(t)=−16t^2+v0t+h0 feet where t is the amount of
asked by Anonymous on October 24, 2016 
physics
A plane is flying horizontally at a height of 500 m and a constant speed of 429 km/h when an object is projected vertically downward at an initial speed of 35.0 m/s. If air resistance is neglected, the average vertical component
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