Physics

A ball is projected upward at time t= 0.0s, from a point on the roof 10m above the ground. The ball rises, then falls until it strikes the ground. The initial velocity of the ball is 58.5 m/s. At time t=5.97s, what is the approximate velocity of the ball? Neglect air resistance.

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  1. Solve this equation using t = 5.97:

    V = Vo - g t = 58.5 - 9.8 t

    That will be zero, indicating that the ball is at its highest elevation.

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  2. Why'd you use 9.8?

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  3. Because the acceleration of gravity (g) is 9.8 m/s^2.

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  4. Oh, okay, thanks.

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  5. jip-;

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  6. how'd you get zero?

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