The value of Kc for the reaction below is 1.6

C(s)+CO2(g)=2CO(g)
What is the equilibrium concentration of CO when [CO2]=.50M?
The usual ICE table doesn't work for me.

C(s)+CO2(g)=2CO(g)
I - 0
C -x +2x
E .50 +2x

1.6=[2x]^(2)/(.50)
That's how I did it but the answer is .89 and I didn't get that.

I don't get 0.89 either. What I don't know is about the equilibrium. Is that 0.50 quoted for CO2 equilibrium concn or initial concn? I worked it both ways and I obtained 0.80 if the 0.5M CO2 is at equilibrium. If initial then I used

1.6 = (2x)^2/(0.5-x) and obtained 0.29.

equi eq:

1.6=x^2/0.5 ; x= equi conc [CO]
x=0.894427191
do not consider [C] since it exists as solid in the equation

To determine the equilibrium concentration of CO (carbon monoxide) when [CO2] is 0.50 M, you correctly set up the equation using the given equilibrium constant (Kc) and the expression for the reaction:

Kc = [CO]^2 / [CO2]

Plugging in the given value for Kc (1.6) and the concentration of CO2 ([CO2] = 0.50 M), we have:

1.6 = (2x)^2 / 0.50

To solve for x (the change in concentration of CO when in equilibrium), we can rearrange the equation:

(2x)^2 = 1.6 * 0.50

4x^2 = 0.8

x^2 = 0.8 / 4

x^2 = 0.2

Taking the square root of both sides:

x ≈ √(0.2)

x ≈ 0.447

Therefore, the equilibrium concentration of CO is approximately 0.447 M.

To find the equilibrium concentration of CO, we need to solve for the value of x using the given value of Kc and the initial concentration of CO2.

The balanced equation for the reaction is:
C(s) + CO2(g) = 2CO(g)

Let's start by setting up the expression for Kc:
Kc = [CO]^2 / [CO2]

Given that Kc = 1.6 and [CO2] = 0.50 M, we can substitute these values into the equation:
1.6 = [CO]^2 / 0.50

Now, let's simplify the equation:
1.6 * 0.50 = [CO]^2
0.80 = [CO]^2

To solve for [CO], we need to take the square root of both sides of the equation:
√0.80 = √([CO]^2)

Since concentration values cannot be negative, taking the square root, we get:
[CO] = √0.80

Calculating the square root of 0.80, we find that [CO] ≈ 0.89 M.

So, the equilibrium concentration of CO when [CO2] = 0.50 M is approximately 0.89 M.

If you obtained a different answer, please recheck your calculations and ensure that you followed the steps correctly.