A rectangular conducting homogeneous (which means the material is the same throughout) block has dimensions 1cm×2cm×3cm . A voltage V is applied between all opposite faces of the block and the corresponding currents were recorded. What is the maximum current measured in Amps if the minimum current recorded is 1mA.
To find the maximum current measured in Amps, we need to consider the dimensions of the block and the resistance of the material. Assuming the material has uniform resistance throughout, we can use Ohm's Law to calculate the maximum current.
Ohm's Law states that the current (I) flowing through a conductor is directly proportional to the voltage (V) applied across it and inversely proportional to the resistance (R) of the conductor. Mathematically, this can be expressed as:
I = V / R
In this case, we are given the voltage (V) applied across the opposite faces of the block, but we need to find the resistance (R) of the block.
The resistance of a conductor can be calculated using the formula:
R = ρ * (L / A)
Where:
- R is the resistance
- ρ (rho) is the resistivity of the material (constant value)
- L is the length of the conductor
- A is the cross-sectional area of the conductor
Since the block is rectangular, we can determine the length (L) and the cross-sectional area (A) using the given dimensions.
L = 3 cm (the length of the block)
A = 1 cm x 2 cm (the cross-sectional area of the block)
Now, let's calculate the resistance (R) using these values.
Next, we need to find the resistivity (ρ) of the material. Assume that the resistivity of the material is known or provided.
Once we have the resistivity (ρ) and the resistance (R), we can use Ohm's Law to calculate the maximum current (I) as follows:
I = V / R
Here, V is the voltage applied (given or known) and R is the calculated resistance.
Substitute the known values into the equation and solve for I to find the maximum current in Amps.