the ka of hypochlorous acid hclo is 3.5 x 10^-8. What is Kb for the hypochlorite ion?

2.8

To find Kb for the hypochlorite ion, we can use the relationship between Ka and Kb:

Ka × Kb = Kw

Where Kw is the ion product constant for water at a given temperature, which is equal to 1.0 x 10^-14.

We can rearrange the equation to solve for Kb:

Kb = Kw / Ka

Substituting the given value for Ka:

Kb = (1.0 x 10^-14) / (3.5 x 10^-8)

Now, let's calculate Kb:

Kb ≈ 2.86 x 10^-7

Therefore, Kb for the hypochlorite ion (ClO-) is approximately 2.86 x 10^-7.

To find Kb for the hypochlorite ion (ClO-), we can use the relationship between Ka and Kb for a conjugate acid-base pair.

The Ka expression for hypochlorous acid (HClO) is:

Ka = [H+][ClO-] / [HClO]

Since we know the value of Ka for HClO (3.5 x 10^-8), we can rearrange this equation to solve for [ClO-]:

[ClO-] = (Ka * [HClO]) / [H+]

Now, the Kb expression for the hypochlorite ion (ClO-) is:

Kb = [OH-][HClO] / [ClO-]

We can use the fact that Kw (the water dissociation constant) is equal to [H+][OH-] = 1.0 x 10^-14, to substitute [OH-]:

[OH-] = Kw / [H+]

Now we can substitute these values into the Kb expression for ClO-:

Kb = ([H+][OH-][HClO]) / [ClO-]
= ([H+][OH-][HClO]) / ((Ka * [HClO]) / [H+])
= (Kw * [H+]) / Ka

Now, we can plug in the known values:

Kw = 1.0 x 10^-14
Ka = 3.5 x 10^-8

Kb = (1.0 x 10^-14 * [H+]) / (3.5 x 10^-8)

To calculate Kb, we need the concentration of [H+]. If the solution is not given, we can assume it to be neutral (pH = 7) for water. In that case, [H+] = 1.0 x 10^-7 M.

Kb = (1.0 x 10^-14 * 1.0 x 10^-7) / (3.5 x 10^-8)

Now you can evaluate this expression using a calculator to find the value of Kb.

KaKb = Kw