Consider the reaction CO3^-2+H2O<==>HCO3^+OH^-. Kb for CO3^-2 is 2.1x10^-4 at 25 Celsius . What is Ka for the HCO3^- ion at 25 Celsius?
wouldn't that be 1/2.1E-4? That's the reverse of the equation.
To find the Ka value for the HCO3- ion, we can use the relationship between Ka and Kb for a conjugate acid-base pair. The equation is as follows:
Ka × Kb = Kw
where Kw is the ion product of water, which is equal to 1.0 × 10^-14.
In this case, we are given the Kb value for the CO3-2 ion, which is 2.1 × 10^-4. To find the Ka value for the HCO3- ion, we need to rearrange the equation:
Ka = Kw / Kb
Plugging in the known values, we have:
Ka = (1.0 × 10^-14) / (2.1 × 10^-4)
Calculating this expression will give you the value for Ka.