A particle starts moving with acceleration 2 m/s2. distance travelled by it in 5th half second is..??
2.25 m
To calculate the distance traveled by the particle in the 5th half second, we need to find the time taken to reach the 5th half second and then use the formula for the distance traveled.
In this case, the acceleration of the particle is given as 2 m/s². We know that acceleration is the rate of change of velocity over time. Since the acceleration is constant, we can use the equation:
v = u + at
Where:
v = final velocity
u = initial velocity (which we assume to be zero since the problem doesn't provide any information about it)
a = acceleration
t = time
Since the initial velocity is zero, the equation simplifies to:
v = at
To find the time taken to reach the 5th half second, we multiply 0.5 s (given as a half second) by 5:
t = 0.5s * 5 = 2.5s
Now that we have the time, we can calculate the final velocity:
v = at
= 2 m/s² * 2.5s
= 5 m/s
To find the distance traveled, we use the equation:
s = ut + 0.5at²
Since the initial velocity is zero, the equation simplifies to:
s = 0.5at²
= 0.5 * 2 m/s² * (2.5s)²
= 0.5 * 2 m/s² * 6.25s²
= 6.25 m
Therefore, the distance traveled by the particle in the 5th half second is 6.25 meters.