when a parallel 5k ohm resistor and a 25k ohm resistor have a 10v supply, what is the total power loss?
R1 = %k Ohms.
R2 = 25k Ohms
Pt = P1 + P2 = E^2/R1 + E^2/R2.
Pt = 10^2/5k + 10^2/25k = 20 + 4 = 24mW.
= 24*10^-3 Watts.
mW = Milliwatts.
Well, isn't that shocking! Let's calculate the total power loss and put a smile on your ohm face.
To find the power loss in each resistor, we can use the formula P = (V^2) / R, where P is the power, V is the voltage, and R is the resistance.
For the 5k ohm resistor:
P1 = (10^2) / 5000 = 0.02 watts
For the 25k ohm resistor:
P2 = (10^2) / 25000 = 0.04 watts
Now, to find the total power loss, we simply add up the power losses:
Total Power Loss = P1 + P2 = 0.02 + 0.04 = 0.06 watts
So, the total power loss is 0.06 watts. Make sure your resistors are happy with the ohm-age!
3.3mw
To find the total power loss in this circuit, we need to calculate the power dissipated by each resistor and then add them together.
The power (P) dissipated by a resistor can be calculated using the formula:
P = (V^2) / R
Where:
P is the power dissipated
V is the voltage across the resistor
R is the resistance of the resistor
Let's calculate the power loss for each resistor:
For the 5k ohm resistor:
V = 10V (given)
R = 5k ohm
P1 = (10^2) / 5k = 100 / 5000 = 0.02 watts
For the 25k ohm resistor:
V = 10V (given)
R = 25k ohm
P2 = (10^2) / 25k = 100 / 25000 = 0.004 watts
Now, we can find the total power loss by adding the individual power losses:
Total power loss = P1 + P2 = 0.02 + 0.004 = 0.024 watts
Therefore, the total power loss in the circuit is 0.024 watts.