Four times a certain number is the same as the number increased by 78. Find the number
i thought it was 20.plz help
4x = x + 78
3x = 78
x = 26
4x=x+78
4(20)=20+78
80=98
no
i did guess and check
4(26)=26+78
104=104
To find the number, let's set up an equation based on the information given.
Let the certain number be represented by "x."
According to the problem, "Four times a certain number is the same as the number increased by 78," can be written as:
4x = x + 78
We can solve this equation to find the value of x.
Subtracting x from both sides:
4x - x = x + 78 - x
3x = 78
Dividing both sides by 3:
3x/3 = 78/3
x = 26
Therefore, the number is 26.
To find the number, let's first set up an equation based on the given information.
The problem states that four times a certain number is the same as the number increased by 78. Let's call the certain number "x".
The equation can be written as:
4x = x + 78
To solve for x, we can start by isolating the variable x on one side of the equation. We can do this by subtracting x from both sides:
4x - x = x + 78 - x
This simplifies to:
3x = 78
Now, to determine the value of x, we divide both sides of the equation by 3:
3x/3 = 78/3
x = 26
Therefore, the number is 26.