CORRECTION
(a). 500g of copper is heated from 30 degree celcius to 120 degree celcius, what is the quantity of heat supplied?(b). If the same quantity of heat is supplied to 300g of water initial at 30 degree celcius. What will be the final temperature.
To answer these questions, we need to use the principle of specific heat capacity. The specific heat capacity is the amount of heat energy required to raise the temperature of a specific substance by a certain amount.
(a) The specific heat capacity of copper is approximately 0.385 J/g°C. To find the quantity of heat supplied, we can use the formula:
Q = m * c * ΔT
Where:
Q is the quantity of heat supplied (in Joules)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (in J/g°C)
ΔT is the change in temperature (in °C)
Given:
m = 500g
c = 0.385 J/g°C
ΔT = 120°C - 30°C = 90°C
Now, substitute the given values into the formula:
Q = 500g * 0.385 J/g°C * 90°C
Q = 17325 Joules
Therefore, the quantity of heat supplied to 500g of copper is 17325 Joules.
(b) To find the final temperature of water after the same quantity of heat is supplied, we can use the formula:
Q = m * c * ΔT
Given:
m = 300g
c = 4.184 J/g°C (specific heat capacity of water)
ΔT = final temperature - initial temperature
Since we want to find the final temperature, we can rearrange the formula to solve for ΔT:
ΔT = Q / (m * c)
Substitute the values into the formula:
ΔT = 17325 Joules / (300g * 4.184 J/g°C)
ΔT ≈ 13.11°C
To find the final temperature, we add ΔT to the initial temperature:
Final temperature = 30°C + 13.11°C
Final temperature ≈ 43.11°C
Therefore, the final temperature of 300g of water, initially at 30°C, after the same quantity of heat is supplied, will be approximately 43.11°C.