How many moles of water are produced by the complete combustion of 14.4g of C5H12?
Oh, I see we're playing with moles and combustion. Well, buckle up, because chemistry can be quite a gas! To find out how many moles of water are produced by the complete combustion of 14.4g of C5H12, we need to break out our lab coats and do some calculations.
First, we need to find the molar mass of C5H12. Carbon (C) has a molar mass of approximately 12.01 g/mol, while hydrogen (H) has a molar mass of about 1.01 g/mol. Since C5H12 has 5 carbon atoms and 12 hydrogen atoms, we can multiply the respective molar masses and add them up:
(5 * 12.01 g/mol) + (12 * 1.01 g/mol) = 60.05 g/mol + 12.12 g/mol = 72.17 g/mol
Now, we can convert the mass of C5H12 to moles by dividing the given mass (14.4g) by the molar mass:
14.4 g / 72.17 g/mol ≈ 0.1996 mol
The balanced equation for the combustion of C5H12 shows that for every 1 mol of C5H12, we get 8 mol of water:
C5H12 + 8O2 -> 5CO2 + 6H2O
Therefore, the number of moles of water produced is (0.1996 mol * 6 mol H2O / 1 mol C5H12) = 1.1976 mol of water.
So, approximately 1.1976 moles of water are produced by the complete combustion of 14.4g of C5H12. Don't worry, though, this combustion reaction doesn't go up in smoke.
To determine the number of moles of water produced, we need to first balance the equation for the combustion of C5H12:
C5H12 + ____ O2 -> ____ CO2 + ____ H2O
We have 14.4g of C5H12, so we can use the molar mass of C5H12 to convert grams to moles. The molar mass of C5H12 is:
C: 12.01 g/mol x 5 = 60.05 g/mol
H: 1.01 g/mol x 12 = 12.12 g/mol
Total molar mass of C5H12 = 60.05 g/mol + 12.12 g/mol = 72.17 g/mol
Using the balanced equation, we can determine the stoichiometric ratio between C5H12 and H2O. From the balanced equation, we can see that for every 1 mol of C5H12 combusted, 8 moles of H2O are produced.
Now we can set up the conversion factor:
(14.4 g C5H12) x (1 mol C5H12 / 72.17 g C5H12) x (8 mol H2O / 1 mol C5H12) = ? mol H2O
Calculating this expression will give us the number of moles of H2O produced.
1.197
C5H12 + 8O2 ==> 5CO2 + 6H2O
mols C5H12 = grams/molar mass
Use the coefficients to convert mols C5H12 to mols H2O.