Need help with problem
(Molarity) How many grams of NaOH are required to prepare 500.0mL
of a 2.00 M solution?
mass=Molarity*volume*molmass
DR BOB IS THE ANSWER 40g
yes
To solve this problem, we need to use the equation for molarity:
Molarity (M) = moles of solute / volume of solution in liters
First, we need to convert the given volume from milliliters to liters:
Volume of solution = 500.0 mL = 500.0 mL / 1000 mL/L = 0.500 L
Next, we rearrange the equation to solve for moles of solute:
Moles of solute = Molarity x Volume of solution
Substituting the given values:
Moles of solute = 2.00 M x 0.500 L = 1.00 moles
Finally, we need to convert moles of solute to grams using the molar mass of NaOH.
The molar mass of NaOH is:
Na (sodium) = 22.99 g/mol
O (oxygen) = 16.00 g/mol
H (hydrogen) = 1.01 g/mol
So, the molar mass of NaOH is:
Na (22.99 g/mol) + O (16.00 g/mol) + H (1.01 g/mol) = 39.00 g/mol
Now we can calculate the grams of NaOH:
Grams of NaOH = Moles of solute x Molar mass of NaOH
Substituting the values:
Grams of NaOH = 1.00 moles x 39.00 g/mol = 39.00 grams
Therefore, you would need 39.00 grams of NaOH to prepare a 500.0 mL solution with a molarity of 2.00 M.