A 8.5 x 10^-3 M solution of acetic acid is 4.6% ionized at 25 degree Celsius. in a 8.5 X 10^-4 M solution, the percentage of ionization would be?
A.the same
B.>4.6%
C.<4.6%
D.zero
E.100%
greater. The more dilute you make it, the more inonized it becomes.
To determine the answer, we can use the concept of ionization and the initial concentration of acetic acid. The ionization of acetic acid is represented by the equation:
CH3COOH ⇌ CH3COO- + H+
Given that the 8.5 x 10^-3 M solution is 4.6% ionized, we can calculate the concentration of the ions:
concentration of ions = 4.6% × 8.5 x 10^-3 M = 0.046 × 8.5 x 10^-3 M = 0.000391 M
Now, let's calculate the percentage of ionization for the 8.5 x 10^-4 M solution:
concentration of ions = ? × 8.5 x 10^-4 M
To find the percentage of ionization, we divide the concentration of ions by the initial concentration of acetic acid and multiply by 100:
percentage of ionization = (concentration of ions / initial concentration) × 100
Using the information given:
0.000391 M / (8.5 x 10^-4 M) × 100 = 46%
Therefore, in a 8.5 x 10^-4 M solution, the percentage of ionization would be 46%, which is greater than 4.6%. Hence, the answer is B.>4.6%.
To determine the percentage of ionization in the 8.5 x 10^-4 M solution, we can start by understanding the relationship between the concentration of the solution and the percentage of ionization.
The percentage of ionization of a weak acid is given by the expression:
% Ionization = (Concentration of ionized acid / Initial concentration of acid) * 100
In this case, we are given that a 8.5 x 10^-3 M solution of acetic acid is 4.6% ionized at 25 degrees Celsius. So, we can write:
4.6 = (Concentration of ionized acid / 8.5 x 10^-3) * 100
Next, we can rearrange the equation to solve for the concentration of ionized acid:
Concentration of ionized acid = (4.6 / 100) * 8.5 x 10^-3
Now we can substitute this value into the equation to find the percentage of ionization in the 8.5 x 10^-4 M solution:
% Ionization = (Concentration of ionized acid / 8.5 x 10^-4) * 100
Plugging in the values:
% Ionization = [(4.6 / 100) * 8.5 x 10^-3] / 8.5 x 10^-4 * 100
% Ionization = (4.6 / 100) * 100
Simplifying this expression, we get:
% Ionization = 4.6%
Therefore, the percentage of ionization in the 8.5 x 10^-4 M solution would be the same as in the 8.5 x 10^-3 M solution. The answer is A. The same.