how many grams of Na2SO4 can be produced by the reaction of 250g of NaOH with sufficient H2SO4?
2NaOH + H2SO4 ==> Na2SO4 + 2H2O
mols NaOH = grams/molar mass
Convert mols NaOH to mols Na2SO4 using the coefficients in the balanced equation.
Now convert mols Na2SO4 to g. grams = mol x molar mass.
To determine the number of grams of Na2SO4 that can be produced by the reaction, we need to consider the balanced chemical equation and the molar masses of the compounds involved.
The balanced chemical equation for the reaction between NaOH and H2SO4 is:
2 NaOH + H2SO4 → Na2SO4 + 2 H2O
From the equation, we can see that for every 2 moles of NaOH, we produce 1 mole of Na2SO4.
Step 1: Calculate the number of moles of NaOH:
Given: Mass of NaOH = 250g
Molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 39.996 g/mol ≈ 40g/mol
Number of moles of NaOH = Mass of NaOH / Molar mass of NaOH
= 250g / 40g/mol
= 6.25 mol
Step 2: Calculate the number of moles of Na2SO4:
Using the balanced chemical equation, we know that 2 moles of NaOH produce 1 mole of Na2SO4.
Number of moles of Na2SO4 = Number of moles of NaOH / 2
= 6.25 mol / 2
= 3.125 mol
Step 3: Calculate the mass of Na2SO4:
To find the mass of Na2SO4, we multiply the number of moles by the molar mass of Na2SO4.
Molar mass of Na2SO4 = 22.99 g/mol + 32.06 g/mol + (4 × 16.00 g/mol)
= 87.04 g/mol
Mass of Na2SO4 = Number of moles of Na2SO4 × Molar mass of Na2SO4
= 3.125 mol × 87.04 g/mol
= 271.25 g
Therefore, approximately 271.25 grams of Na2SO4 can be produced by the reaction of 250 grams of NaOH with sufficient H2SO4.
To determine the number of grams of Na2SO4 produced, we need to use stoichiometry, which is the relationship between the amounts of reactants and products in a chemical reaction.
First, let's write the balanced chemical equation for the reaction between NaOH and H2SO4:
2 NaOH + H2SO4 -> Na2SO4 + 2 H2O
From the balanced equation, we can see that 2 moles of NaOH react with 1 mole of H2SO4 to produce 1 mole of Na2SO4.
Next, we need to convert the given mass of NaOH to moles.
The molar mass of NaOH is calculated as follows:
Na: 22.99 g/mol
O: 16.00 g/mol
H: 1.01 g/mol
NaOH: 22.99 + 16.00 + 1.01 = 40.00 g/mol
To convert grams of NaOH to moles, we will use the formula:
moles = mass (g) / molar mass (g/mol)
moles of NaOH = 250 g / 40.00 g/mol ≈ 6.25 mol
Since the stoichiometry ratio between NaOH and Na2SO4 is 2:1, we can conclude that the number of moles of Na2SO4 produced is also 6.25 moles.
Finally, we convert moles of Na2SO4 to grams using the molar mass of Na2SO4:
Na: 22.99 g/mol
S: 32.07 g/mol
O: 16.00 g/mol
Na2SO4: (2 * 22.99) + 32.07 + (4 * 16.00) = 142.04 g/mol
grams of Na2SO4 = moles of Na2SO4 * molar mass of Na2SO4
= 6.25 mol * 142.04 g/mol
≈ 887.5 g
Therefore, approximately 887.5 grams of Na2SO4 can be produced from the reaction.