A locker combination has three nonzero digits, and digits cannot be repeated. If the first two digits are even, what is the probability that the third digit is even?
I think the answer is 2/7
A locker combination has three nonzero digits, and digits cannot be repeated. The first two digits are 1 and 2. What is the probability that the third digit is 3?
I'm sorry but i don't know the answer to your question, but i need help on this question:
A locker combination has three nonzero digits, and digits cannot be repeated. If the first two digits are even, what is the probability that the third digit is even?
ex. 3 and 4 chance of something, it would be .75 because 4 (100) x 3 of 100 is 75 so its .75!
A locker combination has three nonzero digits, and digits cannot be repeated. If the first two digits are even, what is the probability that the third digit is even
Assuming the digits are from 1 to 9, then the even is 2,4,6,8 and the odd are 1,3,5,7,9.
Prodd(ways/choices)=5/(2+5)