A golf ball with a mass of 50.3 g can be blasted from rest to a speed of 72.1 m/s during impact with a club head. Assume that the impact lasts only about 0.910 ms. Calculate the change in momentum of the ball.

Calculate the average force applied.

To calculate the change in momentum of the golf ball, we can use the following formula:

Change in momentum (Δp) = mass (m) × final velocity (v) - initial velocity (u)

Given:
Mass of the golf ball (m) = 50.3 g = 0.0503 kg
Initial velocity (u) = 0 m/s (since it is initially at rest)
Final velocity (v) = 72.1 m/s

Using the formula, we have:
Δp = 0.0503 kg × 72.1 m/s - 0 m/s
Δp = 3.614 kg·m/s

Therefore, the change in momentum of the golf ball is 3.614 kg·m/s.

Now, let's calculate the average force applied using the equation:

Average force (F_avg) = Change in momentum (Δp) / time (t)

Given:
Δp = 3.614 kg·m/s
Time (t) = 0.910 ms = 0.910 × 10^-3 s

Using the equation, we have:
F_avg = 3.614 kg·m/s / (0.910 × 10^-3 s)
F_avg ≈ 3969.2 N

Therefore, the average force applied to the golf ball is approximately 3969.2 Newtons.