Calculate a person's hang time if he moves horizontally 2 m during a 1.39 m high-jump.
To calculate the hang time of a person during a high-jump, we need to use the principles of projectile motion. Hang time refers to the total time the person is in the air during the jump.
First, we need to determine the vertical component of the jump, which is the maximum height reached by the person. In this case, the height of the jump is given as 1.39 m.
We know that the time it takes for an object to reach its maximum height during vertical motion is given by the formula:
t = √(2h/g)
Where:
t = time taken to reach maximum height
h = height
g = acceleration due to gravity (9.8 m/s²)
Plugging in the values:
t = √(2 × 1.39 / 9.8)
t ≈ √(0.282 / 9.8)
t ≈ √0.0288
t ≈ 0.17 s (rounded to two decimal places)
Now, since hang time refers to the total time in the air, we need to consider both the upward and downward motion. Therefore, the total hang time can be calculated by doubling the time taken to reach the maximum height:
Total hang time = 2 × t ≈ 2 × 0.17 ≈ 0.34 s
Therefore, the person's hang time during the high jump is approximately 0.34 seconds.
Keep in mind that this calculation assumes no air resistance and ideal conditions. In reality, air resistance can slightly affect the result.
To go up and down H = 1.39 meters requires
2*sqrt(2H/g)= 1.07 seconds
regardless of how far the jumper moves horizontally. They provided the 2 meter distance to trick you.