if a girl pulls on a 15 kg wagon with a constant horizontal force of 35N.Her friend pushes on the wagon in the same direction with a constant horizontal force of 10 N. and there is a friction force of 15 N. I need to draw a diagram of this problem and calculate the Net Force on the wagon. If there are no other horizontal forces on the wagon, and all the forces on the diagram are constant, what is the wagon's acceleration in meters per second? Could you please give me a step by step formula for this problem?
Sure! Let's break it down step by step to solve this problem:
Step 1: Draw a diagram:
You can start by drawing a simple diagram to visualize the situation. Draw a horizontal line and represent the wagon as a rectangle. Place an arrow pointing to the right above the wagon to represent the force exerted by the girl. Next, draw another arrow pointing to the right below the wagon to represent the force exerted by the friend. Finally, place an arrow pointing to the left below the wagon to represent the friction force.
->
________________
| |
| Wagon |
|_______________|
<-
(Girl's Force) (Friend's Force) (Friction Force)
Step 2: Calculate the net force:
The net force is the sum of all the forces acting on the wagon. In this case, since all the forces are acting in the same direction (to the right), we can simply add them up. Using the given values:
Net Force = Girl's Force + Friend's Force - Friction Force
= 35N + 10N - 15N
= 30N
Step 3: Calculate the acceleration:
The net force acting on an object is related to its acceleration through Newton's second law of motion: F = ma, where F is the net force, m is the mass, and a is the acceleration. In this case, the mass of the wagon is given as 15 kg. Rearranging the formula, we get:
a = F/m
= 30N / 15kg
= 2 m/s^2
So, the wagon's acceleration is 2 m/s^2.
I hope this helps! Let me know if you have any further questions.