Cr + Sn2+

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To balance the chemical equation Cr + Sn2+, we first need to determine the oxidation states of each element.

The oxidation state of chromium (Cr) is typically +3, but can also be +2 or +6 in certain compounds.

The oxidation state of tin (Sn) in Sn2+ is +2.

To balance the equation, we need to ensure that the number of each type of atom is the same on both sides of the equation. Here's the balanced equation:

2Cr + Sn2+ → 2Cr3+ + Sn

Explanation:
1. Start by balancing the tin (Sn) atoms. Since there is one tin atom on the left side and one on the right side, the tin atoms are already balanced.

2. Next, balance the chromium (Cr) atoms. Since there are two chromium atoms on the left side, we need to have two chromium atoms on the right side as well. Adding a coefficient of 2 in front of Cr on the right side balances the number of chromium atoms.

3. Finally, balance the charges. On the left side, the net charge is +2 from Sn2+. On the right side, there are two Cr3+ ions with a net charge of +6. So, the charges are balanced.

The balanced equation is now 2Cr + Sn2+ → 2Cr3+ + Sn.