how do I calculate the mass of ammonium sulfate formed from the complete reaction of 700 grams of ammonia?
(NH4)2 SO4
how many moles of NH3 is in 700 grams. Figure that.
Now,in ammonium sulfate figure it like this (NH3 + H)2SO4. Put that number of moles you figured of NH3, and half that is the moles of ammonium sulfate. What mass is that?
mass=1/2 numbermolesNH3*molmass(NH4)2SO4