A standard man uses a bicycle of mass 30 kg to travel at constant speed along a 5 km long road up
a hill. The hill rises 250 m above the starting point and the man needs 30 minutes to get to the top.
How much work does the man do during the trip? What was the power use during the trip?
Work=mgh==30•9.8•250 =...
Power =mgh/t=30•9.8•250/30•60 =...
Hahaha the person who asked this question in totally in my Physics for the Life Sciences course at UOIT. Assignment 2 ;)
A standard man uses a bicycle of mass 30 kg to travel at constant speed along a 5 km long road up
a hill. The hill rises 250 m above the starting point and the man needs 30 minutes to get to the top.
(a) How much work does the man do during the trip?
(b) What was the power use during the trip?
lmao LOL its so true im deff in that physics for life science class Joe needs to make easier questions :(
same and yea he does this is nuts
sitting in the library trying to finish this before class... fail im so lost
To find the work done by the man during the trip, we need to calculate the change in potential energy as he travels up the hill. The work done is equal to the change in potential energy.
First, let's calculate the change in potential energy:
Change in potential energy = mass * g * height
where mass = 30 kg (mass of the man+bicycle), g = 9.8 m/s^2 (acceleration due to gravity), and height = 250 m
Change in potential energy = 30 kg * 9.8 m/s^2 * 250 m = 73,500 J
Therefore, the man does 73,500 J of work during the trip.
Next, let's calculate the time taken to travel the distance:
Given that the man needs 30 minutes to get to the top, we need to convert it to seconds:
Time = 30 minutes = 30 * 60 seconds = 1800 seconds
Now, let's calculate the power used during the trip:
Power = work done / time taken
Power = 73,500 J / 1800 s = 40.833 W
Therefore, the power used during the trip is approximately 40.833 Watts.