ABCD is a trapezoid with AB parallel to DC. If AB = 25, BC = 24, CD = 50 and AD = 7, what is the area of ABCD?
in trapezoid ABCD,12 is perpendicular to 29
To find the area of trapezoid ABCD, we can use the formula:
Area = (1/2) * (sum of the lengths of the parallel sides) * (distance between the parallel sides)
In this case, AB and DC are the parallel sides, and BC is the distance between them.
Given:
AB = 25
BC = 24
CD = 50
AD = 7
To use the formula, we need to find the sum of the lengths of AB and DC.
Since AB is parallel to DC, their lengths are equal, so AB + DC = 2(AB).
We can find AB + DC = 2(AB) by substituting the given values:
AB + DC = 2(25) = 50
Now we can substitute the values into the formula:
Area = (1/2) * (AB + DC) * BC
Area = (1/2) * 50 * 24
Area = 25 * 24
Area = 600 square units
Therefore, the area of trapezoid ABCD is 600 square units.