ABCD is a trapezoid with AB parallel to DC. If AB = 25, BC = 24, CD = 50 and AD = 7, what is the area of ABCD?

in trapezoid ABCD,12 is perpendicular to 29

To find the area of trapezoid ABCD, we can use the formula:

Area = (1/2) * (sum of the lengths of the parallel sides) * (distance between the parallel sides)

In this case, AB and DC are the parallel sides, and BC is the distance between them.

Given:
AB = 25
BC = 24
CD = 50
AD = 7

To use the formula, we need to find the sum of the lengths of AB and DC.

Since AB is parallel to DC, their lengths are equal, so AB + DC = 2(AB).

We can find AB + DC = 2(AB) by substituting the given values:

AB + DC = 2(25) = 50

Now we can substitute the values into the formula:

Area = (1/2) * (AB + DC) * BC

Area = (1/2) * 50 * 24

Area = 25 * 24

Area = 600 square units

Therefore, the area of trapezoid ABCD is 600 square units.