What is the total kinetic energy if a 0.30 kg block is sliding on a smooth horizontal surface at 2.5 m/s, heading towards a light spring that is in equilibrium?

To find the total kinetic energy, we first need to understand the formula for kinetic energy.

The formula for kinetic energy (KE) is:

KE = 0.5 * mass * velocity^2

Where:
- KE is the kinetic energy
- mass is the mass of the object
- velocity is the velocity of the object

In this case, the mass of the block is given as 0.30 kg, and the velocity is given as 2.5 m/s.

Now, we can substitute the values into the formula:

KE = 0.5 * 0.30 kg * (2.5 m/s)^2

Let's calculate it:

KE = 0.5 * 0.30 kg * (2.5 m/s)^2
= 0.5 * 0.30 kg * 6.25 m^2/s^2
= 0.9375 Joules

Therefore, the total kinetic energy of the 0.30 kg block sliding at 2.5 m/s is 0.9375 Joules.