An organic compound that has the empirical formula CHO has a molecular mass of 145 amu. Its molecular formula is?

empirical formula mass = 12+1+16 = 29

145/29 = 5
molecular formula = (CHO)5 or C5H5O5 and molar mass is ?

the molar mass of C5H5O5 is 145. right?

right.

(5*12)+*5*1)+(5*16) = 145

thnk u so much

To determine the molecular formula of an organic compound given its empirical formula and molecular mass, we need to calculate the ratio between the empirical formula mass and the molecular mass. By doing this, we can determine the multiplier needed to convert the empirical formula into the molecular formula.

1. Start by calculating the empirical formula mass:
- The empirical formula contains one carbon (C), one hydrogen (H), and one oxygen (O).
- The atomic mass of carbon (C) is approximately 12.01 amu.
- The atomic mass of hydrogen (H) is approximately 1.01 amu.
- The atomic mass of oxygen (O) is approximately 16.00 amu.
- Calculate the empirical formula mass: (12.01 amu for C) + (1.01 amu for H) + (16.00 amu for O) = 29.02 amu.

2. Divide the molecular mass of the compound by the empirical formula mass to find the multiplier:
- Given molecular mass: 145 amu
- Multiplier = Molecular mass / Empirical formula mass = 145 amu / 29.02 amu ≈ 5

3. Multiply each atom's subscript in the empirical formula by the multiplier:
- Empirical formula: CHO
- Multiplier: 5
- Molecular formula: (C1H1O1) × 5 = C5H5O5

Therefore, the molecular formula of the compound with the empirical formula CHO and a molecular mass of 145 amu is C5H5O5.