I burned a candle for 3 minutes. It started with a mass of 38.53g (C25H52). It ended with a mass of 38.48g. What mass of water was produced in three minutes? If I burned the candle all day, what mass of the candle would react?
2C25H58 + 79O2 ==> 50CO2 + 58H2O
mols C25H58 = (38.53-38.48)/molar mass = about 0.00014 but you should be more accurate.
Convert mols C25H58 to mol H2O using the coefficients in the balanced equation.
Now convert that to grams. g = mols H2O x molar mass H2O.
To find the mass of water produced during the burning of the candle for 3 minutes, we need to calculate the difference in mass of the candle before and after the burn.
The initial mass of the candle was 38.53g, and the final mass was 38.48g.
To determine the mass of water produced, subtract the final mass from the initial mass:
38.53g - 38.48g = 0.05g
Therefore, 0.05g of water was produced during the 3-minute burn.
If you burned the candle all day, we need to make some assumptions. Assuming the rate of burning remains constant throughout the day, we can find the mass of the candle that would react based on the time ratio. However, it's important to note that the assumption of a constant burning rate may not be accurate.
Let's assume that the candle burns at a rate of 0.05g of candle per minute.
The burn time for one day is 24 hours × 60 minutes = 1440 minutes.
To calculate the mass of the candle that would react, multiply the burn rate by the burn time:
0.05g/minute × 1440 minutes = 72g
Therefore, if you burned the candle all day, approximately 72g of the candle would react. Keep in mind that this calculation assumes a constant burning rate, which may not reflect the actual burning characteristics of the candle.