This is a repost. I posted a question 2 days ago and the response was wrong. The question was on Probability. The question was One card is selected from a deck of playing cards. Determine the probability of selecting a jack OR a club. use this rule P(A or B) = P(A) + P(B) - P(A and B)
There are 13 clubs and then 3 jacks.
16/52
Using the rule P(J) = 4/52
P(C) = 13/52
P(C + J) = 1/52 the Jack of Clubs
P(jack or club)= pr(jack)+Prob(club)-Prob(both)
= 4/52+13/52-1/52
check that.
To determine the probability of selecting a jack OR a club from a deck of playing cards, we can use the formula P(A or B) = P(A) + P(B) - P(A and B), where A represents selecting a jack and B represents selecting a club.
First, let's find the probability of selecting a jack. In a standard deck of playing cards, there are 4 jacks (one from each suit), so the probability of selecting a jack is P(A) = 4/52 = 1/13.
Next, we need to find the probability of selecting a club. There are 13 clubs in a standard deck, including the jack of clubs, so P(B) = 13/52 = 1/4.
Now, we have to determine the probability of selecting both a jack and a club (jack of clubs). Since there is only one jack of clubs in the deck, the probability of selecting it is P(A and B) = 1/52.
Now we can use the formula P(A or B) = P(A) + P(B) - P(A and B) to calculate the probability of selecting a jack OR a club:
P(Jack or Club) = P(A) + P(B) - P(A and B) = (1/13) + (1/4) - (1/52) = 16/52 = 4/13.
So, the probability of selecting a jack OR a club from a deck of playing cards is 4/13.
I apologize if the previous response was incorrect. Probability calculations can be tricky, but by following the steps above, you should be able to accurately determine the probability in any similar scenario.