How many moles of \rm CaC_2O_4 are present in this kidney stone?
The equilibrium constant, Kc, for the following system is 24.4.
H2(g) + X2(g) 2 HX(g)
At equilibrium, a system contains 0.200 moles of X2 and 0.600 moles of HX in a 4 × 10–3 m3 container. Calculate the number of moles of H2(g) present at equilibrium.
Select one:
a. 0.059 mol
b. 0.074 mol
c. 0.0123 mol
d. 0.295 mol
To determine the number of moles of calcium oxalate (CaC2O4) present in the kidney stone, you need to know the mass of the kidney stone and the molar mass of CaC2O4.
1. Determine the molar mass of CaC2O4:
- Calcium (Ca) has an atomic mass of 40.08 g/mol.
- Carbon (C) has an atomic mass of 12.01 g/mol.
- Oxygen (O) has an atomic mass of 16.00 g/mol.
The molar mass of CaC2O4 is calculated by adding up the atomic masses:
Molar mass of CaC2O4 = (1 x Ca) + (2 x C) + (4 x O) = 40.08 + 2(12.01) + 4(16.00) = 128.09 g/mol.
2. Obtain the mass of the kidney stone:
You'll need information about the mass of the kidney stone. Take note of its units (grams) and record the value.
3. Calculate the number of moles using the mass and molar mass:
Number of moles = Mass of substance (g) / Molar mass (g/mol).
By dividing the mass of the kidney stone (in grams) by the molar mass of CaC2O4 (in grams/mole), you can determine the number of moles of CaC2O4 in the kidney stone.
Remember to convert the units if needed.
Do you have the mass of the kidney stone in grams?