Tiger woods won the Buick Invitational.The following scorecard shows the result of Round1.there are 18 holes?
per round and the table shows the number of times woods got each type of score.
Score on a hole and Number of times score occurred
Eagle (-2) 2
Birdie(-1) 4
Par (0) 10
Bogey (+1 ) 2
1Q.Write his score as the sum of eagles,birdies,pars and bogeys
2Q.What was his final score for the round,when compared to par?
3Q.What answer do you get if you do the arithmetic left to right? (Ans 2 above par)
4Q.Explain why the answers in 2Q and 3Q do not match?
1A. To calculate Tiger Woods' score as the sum of eagles, birdies, pars, and bogeys, you need to know the value associated with each score. In this case, an eagle is -2, a birdie is -1, a par is 0, and a bogey is +1.
So, adding up the number of times each score occurred:
Number of eagles: 2 (-2 x 2) = -4
Number of birdies: 4 (-1 x 4) = -4
Number of pars: 10 (0 x 10) = 0
Number of bogeys: 2 (+1 x 2) = 2
Adding these scores together, we get: -4 + -4 + 0 + 2 = -6.
Therefore, Tiger Woods' score as the sum of eagles, birdies, pars, and bogeys is -6.
2A. To determine Tiger Woods' final score for the round compared to par, we need to add up the sum of scores on each hole. The score for each hole is given by the table.
Number of Eagles: 2 (-2 x 2) = -4
Number of Birdies: 4 (-1 x 4) = -4
Number of Pars: 10 (0 x 10) = 0
Number of Bogeys: 2 (+1 x 2) = 2
Adding these scores together, we get: -4 + -4 + 0 + 2 = -6.
Therefore, Tiger Woods' final score for the round, when compared to par, is -6.
3A. If we do the arithmetic left to right, we get:
-4 + -4 + 0 + 2 = -6
Here, the answer is the same as in question 2.
4A. The reason the answers in question 2 and question 3 match is because addition is associative, meaning that the order in which we add numbers does not affect the result.
In this case, when calculating the final score, regardless of the order in which we add the scores, the sum will be the same: -4 + -4 + 0 + 2 = -6.
So, the answers in question 2 and question 3 match because addition is commutative.