A particle P of mass 2kg is attached to one end of a light rod of length 0.5m which is free to rotate in a verticle
To find the moment of inertia of a system, we need to take into account the various components of the system. In this case, we have a particle P of mass 2kg attached to one end of a light rod of length 0.5m, which is free to rotate about a vertical axis.
The moment of inertia (I) of a point mass (m) rotating about an axis at a distance (r) from the axis of rotation is given by the equation:
I = m * r^2
In this case, the mass (m) of particle P is 2kg. To calculate the moment of inertia, we need to determine the distance (r) of the particle from the axis of rotation.
Since the rod is attached to one end of the particle P, the center of mass of the particle is located at a distance of 0.5m from the axis of rotation. Hence, the distance (r) for calculating the moment of inertia is 0.5m.
Now, we can substitute the values into the equation:
I = m * r^2
= 2kg * (0.5m)^2
= 2 * 0.5^2 kg * m^2
= 1kg * m^2
Therefore, the moment of inertia of the particle P attached to the rod is 1 kg * m^2.