In a group of 200 high school students, 36 are taking biology, 52 are taking Spanish, and 126 are taking neither biology nor Spanish. If one of these 200 students is to be chosen at random, what is the probability that the student chosen is taking biology but not Spanish?
Total # of students = 200
Biology students = 36
Spanish students = 52
Other students = 126
36+52+126 does not even = 200 students total
Did you type this question incorrectly?
its 19%
126 (neither Bio. nor Spanish)
+52 (Spanish)
___
178 (total of students that can't be chosen)
200 (total students)
-178 (total it can't be chosen)
____
22
22/200 = 11/100 = 11%
This is not the only way to solve it.
Well, it seems like a tricky question! But don't worry, I've got a joke that might help.
Why did the amoeba take piano lessons?
Because it wanted to learn CELL-to!
Now, let's get back to the question. We know that there are 36 students taking biology and 52 taking Spanish. However, we don't know how many students are taking both. So to find the number of students taking only biology, let's subtract the number of students taking both from the total number of students taking biology.
36 (biology) - ??? (biology and Spanish) = ??? (only biology)
Unfortunately, without enough information, we can't determine the exact number of students taking only biology. Therefore, we cannot calculate the probability. But hey, at least we had a laugh along the way!
To find the probability that a randomly chosen student is taking biology but not Spanish, we need to calculate the ratio of the number of students taking biology but not Spanish to the total number of students.
We are given that 36 students are taking biology, 52 students are taking Spanish, and 126 students are taking neither biology nor Spanish.
To find the number of students taking biology but not Spanish, we need to subtract the number of students taking both biology and Spanish from the total number of students taking biology.
Let's calculate:
Number of students taking both biology and Spanish = 36
Number of students taking biology but not Spanish = 36 - (number of students taking both biology and Spanish)
= 36 - 0 (since none are taking both biology and Spanish)
= 36
Total number of students = number of students taking biology + number of students taking Spanish + number of students taking neither biology nor Spanish
= 36 + 52 + 126
= 214
Now, we can calculate the probability:
Probability that the student chosen is taking biology but not Spanish = number of students taking biology but not Spanish / total number of students
= 36 / 214
≈ 0.1682 (rounded to four decimal places)
Therefore, the probability that the student chosen is taking biology but not Spanish is approximately 0.1682.