If one light bulb was removed in a circuit I think the others will go out because it is incomplete is this right? I will the remaining lights powered by a 9 volt be dim? I am not sure? I think go black dark because its incomplete.
When a light bulb is removed from a series circuit, it will break the continuity of the circuit, resulting in an open circuit. In this case, the other light bulbs in the circuit will indeed go out because no current can flow through the circuit. So you are correct in thinking that the other lights will go dark.
However, the brightness of the remaining lights in the circuit is not directly dependent on the voltage source (in this case, a 9-volt battery). In a series circuit, the same current flows through each component, so if one light bulb is removed, the current flow is interrupted, causing all the lights to go out. The voltage across each bulb remains the same, but without the current, the bulbs won't produce any light. So the remaining lights will not be dim; they will simply not illuminate at all.
To test this, you can try setting up a simple series circuit with light bulbs and a 9-volt battery. Then, remove one of the bulbs, and you will observe that all the bulbs will go out.