A 1.00 kg block of ice at zero degrees celsius is added to a picnic cooler. How much heat will the ice remove as it melts to water at zero degrees Celsius?
q = mass ice x heat fusion.
To calculate the amount of heat energy absorbed by the ice as it melts, you need to use the equation:
Q = m * ΔHf
Where:
Q = heat energy absorbed (in joules)
m = mass of the ice (in kilograms)
ΔHf = heat of fusion of ice (in joules per kilogram)
For ice, the heat of fusion (ΔHf) is 334,000 J/kg.
Given that the mass of the ice is 1.00 kg, we can substitute these values into the equation:
Q = 1.00 kg * 334,000 J/kg
Q = 334,000 J
Therefore, the ice will remove 334,000 joules of heat energy as it melts to water at zero degrees Celsius.