Janet has 73 coins. Linda has 28 more coins then Janet, but 17 fewer coins than Alan. Sam has 33 fewer coins than Alan. How many more coins does same have than Janet?
My answer is 12 coins, am i right? If not please tell me your answer and how you got it.
Believe it or not, I got 12 too!! That was a little tricky. You must have the problem carefully to get the right answer. That is the key to most word problems. Read.. carefully and slowly.
Janet: 73
Linda: 73 + 28 = 101
Alan: 101 + 17 = 118
Sam: 118 - 33 = 85
Yes, 12 is right.
To find out how many more coins Sam has than Janet, we first need to determine how many coins each person has:
Janet: 73 coins
Linda: 73 + 28 = 101 coins (28 more than Janet)
Alan: 101 + 17 = 118 coins (17 more than Linda)
Sam: 118 - 33 = 85 coins (33 fewer than Alan)
Now, to find out how many more coins Sam has than Janet, we subtract Janet's number of coins from Sam's number of coins:
85 - 73 = 12
So, Sam has 12 more coins than Janet. Your answer of 12 coins is correct!