A wire that is 0.45 m long and carrying a current of 9.5 A is at right angles to a 0.40 T magnetic field. How strong is the force that acts on the wire?
ihatephysics
where is the answer????
To determine the strength of the force acting on a wire carrying a current in a magnetic field, we can use the formula for the magnetic force:
F = BIL
Where:
F is the magnetic force,
B is the magnetic field,
I is the current, and
L is the length of the wire.
Given:
B = 0.40 T (Tesla)
I = 9.5 A (Amperes)
L = 0.45 m (meters)
Now we can substitute the given values into the formula to find the magnetic force:
F = (0.40 T) * (9.5 A) * (0.45 m)
Let's calculate:
F = (0.40) * (9.5) * (0.45)
= 1.71 N
Therefore, the strength of the force acting on the wire is 1.71 Newtons.