7750 Joules of energy is added to a 325 grams stone at 24.0 degrees centigrade. The temperature increases by 75.0 degrees centigrade. What is the specific heat of the stone?
To find the specific heat of the stone, we can use the formula:
Q = m * c * ΔT
Where:
Q is the amount of heat energy transferred to the stone (in Joules)
m is the mass of the stone (in grams)
c is the specific heat of the stone (in J/g°C)
ΔT is the change in temperature of the stone (in °C)
We are given:
Q = 7750 J
m = 325 g
ΔT = 75°C
Substituting these values into the formula, we get:
7750 J = 325 g * c * 75°C
To find the value of c, we can rearrange the equation to solve for c:
c = 7750 J / (325 g * 75°C)
Now we can calculate the specific heat:
c = 0.32 J/g°C
Therefore, the specific heat of the stone is 0.32 J/g°C.