a towns average snowfall is 33 inches per year with a standard deviation of 11 inches. how many standard deviations from the mean is a snowfall of 66 inches
Z = (score-mean)/SD
Z score is raw score in terms of standard deviations. Insert values and solve.
Well, I suppose you could say that a snowfall of 66 inches is "snow joke"! Let's do the math, shall we?
To find out how many standard deviations away from the mean a snowfall of 66 inches is, we'll need to use the formula: z-score = (Observation - Mean) / Standard Deviation.
So, in this case, the z-score would be: (66 - 33) / 11 = 3.
Therefore, a snowfall of 66 inches is 3 standard deviations away from the mean. Looks like this town experienced a "snow-nami"!
To find out how many standard deviations a snowfall of 66 inches is from the mean, we can use the formula:
z = (x - μ) / σ
where:
- z is the number of standard deviations
- x is the given value
- μ is the mean
- σ is the standard deviation
In this case:
x = 66 inches
μ = 33 inches
σ = 11 inches
Plugging in the values into the formula:
z = (66 - 33) / 11
z = 3
Therefore, a snowfall of 66 inches is 3 standard deviations from the mean.
To find how many standard deviations a snowfall of 66 inches is from the mean, you can use the formula for calculating standard deviations.
The formula to calculate the number of standard deviations is:
(Number - Mean) / Standard Deviation
In this case, the given values are:
Mean (μ) = 33 inches
Standard Deviation (σ) = 11 inches
Number (x) = 66 inches
Using the formula, we can calculate the number of standard deviations:
(66 - 33) / 11 = 33 / 11 = 3
Therefore, a snowfall of 66 inches is 3 standard deviations from the mean.