1.) Two people of the same mass climb the same flight of stairs. The first person climbs the stairs in 25 s; the second person does so in 35 s.
a) Which person does more work?Explain
b) Which person produces more power?Explain
2.) Lee pushes a 20 kg mass 10 m across a floor with a horizontal force of 80 N. Calculate the amount of work Lee does.
The work done = potential energy gained = m g h.
That is the same for both since m, g and h are the same for both
The power is the work per unit time.
Power = m g h/t
so smaller t ---> bigger power
1a) W1=W2 = mgh
2a) P1 > P2 , mgh/25 >mgh/35
2) W=Fs=80•10 =800 J
Calculate the work done when a person push acar from stationany position to a
distance of 50m appliny a. force of 200n.
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for minecraft education edition
1) a) The person who climbs the stairs in 25 seconds does more work. Why? Because they're clearly more motivated! They managed to conquer those stairs faster than the second person, which means they exerted more energy and did more work.
b) As for power, the person who climbs the stairs in 25 seconds also produces more power. It's like they have their own internal speed booster! Power is the rate at which work is done, so since the first person completed the same amount of work (climbing the stairs) in less time than the second person, they have a higher power output.
2) To calculate the amount of work Lee does, we can use the equation:
Work = Force × Distance
Given:
Force = 80 N
Distance = 10 m
Plugging in the values:
Work = 80 N × 10 m
Work = 800 Joules
So Lee does 800 Joules of work. That's enough work to impress even the laziest of math textbooks!
1a) To determine which person does more work, we need to calculate the work done by each person. The work (W) done is given by the equation:
W = Force × Distance × Cosine(theta)
Where Force is the applied force, Distance is the displacement, and Cosine(theta) is the angle between the applied force and the direction of displacement.
In this case, both people climb the same flight of stairs, so the distance is the same for both. Also, we can assume that they climb vertically, so the angle between their applied force and the direction of displacement is 0 degrees. Therefore, Cosine(theta) is equal to 1.
Now, let's calculate the work done by each person:
For the first person:
W1 = Force × Distance × Cosine(0)
W1 = Force × Distance
For the second person:
W2 = Force × Distance × Cosine(0)
W2 = Force × Distance
Since the distance and the applied force are the same for both people, the work done by each person is equal. Therefore, both people do the same amount of work.
1b) Power is defined as the rate at which work is done. It is given by the equation:
Power = Work / Time
To determine which person produces more power, we need to calculate the power for each person.
For the first person:
Power1 = Work1 / Time1
For the second person:
Power2 = Work2 / Time2
Since we found that the work done by each person is the same, it means Work1 = Work2. However, the time taken by each person to climb the stairs is different. The first person takes 25 seconds, and the second person takes 35 seconds.
If we divide the same amount of work by a smaller time interval, we get a larger power. Therefore, the person who climbs the stairs in 25 seconds produces more power than the person who takes 35 seconds.
2) The work done by Lee can be calculated using the equation:
W = Force × Distance × Cosine(theta)
In this case, Lee applies a horizontal force of 80 N, and the mass moves a distance of 10 m. If we assume the force is applied horizontally (theta = 0 degrees), then Cosine(theta) is equal to 1.
Plugging in the values:
W = 80 N × 10 m × Cosine(0)
W = 80 N × 10 m
W = 800 N·m
The amount of work Lee does is 800 N·m.