The gravitational force between two objects is 2,000N. They are moved so that the distance between them is four times the original distance. What is the new force between the objects?

(1/4)^2 = 1/16 of 2000 N.

That would be 125 Newtons

F = m1 times m2 divided by r^2

Force is inversely related to r^2
If the distance increases by 4 then the force decreases by 1/4^2 of 1/16

1/16 of 2000 N

To determine the new force between the objects, we can apply the principle of inverse square law for gravitational force. According to this principle, the gravitational force between two objects is inversely proportional to the square of the distance between them.

Let's denote the original distance as "d" and the original force as "F". The new distance between the objects is given as four times the original distance, which means the new distance is 4d.

Now, since the gravitational force is inversely proportional to the square of the distance, when the distance is increased by a factor of four, the force will decrease by the square of that factor. In this case, the factor is 4, so the force will decrease by 4^2 = 16.

Given that the original force F is 2,000 N, we can calculate the new force F' using the equation:

F' = F / (distance factor)^2

F' = 2,000 N / 16

F' = 125 N

Therefore, the new force between the objects is 125 N.