How many grams of NH4Br(Molar Mass=98g)are in 440.0 mL of 1.75Moles NH4Br
1.75 moles in 1000 ml
x moles in 440 ml?
Once you find out the x. Multiply that answer times 98 g.
To find the number of grams of NH4Br in 440.0 mL of a 1.75 M NH4Br solution, you can follow these steps:
Step 1: Calculate the number of moles of NH4Br in the solution.
Molarity (M) is defined as moles of solute per liter of solution. Given that the molarity of NH4Br is 1.75 M and the volume is 440.0 mL, you need to convert the volume from milliliters to liters:
440.0 mL = 440.0 mL / 1000 mL/L = 0.440 L
Moles of NH4Br = Molarity × Volume
Moles of NH4Br = 1.75 mol/L × 0.440 L = 0.77 moles
Step 2: Calculate the mass of NH4Br.
The molar mass of NH4Br is given as 98 g/mol.
Mass of NH4Br = Moles × Molar mass
Mass of NH4Br = 0.77 mol × 98 g/mol = 75.46 grams
Therefore, there are 75.46 grams of NH4Br in 440.0 mL of a 1.75 M NH4Br solution.