A 6 ft pole casts a shadow of 8ft long while a nearby flagpole casts a shadow of 56 ftlong. What is the height of the flagpole?
Cross multiply and solve for x.
6/8 = x/56
the ratio is 6/8 (height actual to shadow)
Flagpole height / 56 = 6/8
flagpole height / 56= 3/4
so, the flagpole height is 56*3 / 4 = 42
7x+4<1_2(4x+3).
The present ages of father and his son are in ration10:3. If the son 15 years old now in how many years will the ratio of their ages be 2 :1 ?
To find the height of the flagpole, we can set up a proportion based on the lengths of the shadows.
Let's denote the height of the flagpole as "x".
According to the given information, the height of the 6 ft pole is proportional to its shadow length, and the height of the flagpole is proportional to its shadow length as well.
The proportion can be set up as follows:
6 ft / 8 ft = x ft / 56 ft
To solve for x, we can cross-multiply and divide:
(6 ft) * (56 ft) = (8 ft) * (x ft)
336 ft = 8x ft
Now divide both sides of the equation by 8:
336 ft / 8 = 8x ft / 8
42 ft = x ft
Therefore, the height of the flagpole is 42 feet.