You have 10.0 L of 1.2 M KNO3. What molarity would the KNO3 solution be if you were to take 2.5 L of it and dilute it to 10.0 L?
1.2M x (2.5/10.0) = ?
Or another way.
mols KNO3 in the 2.5L = M x L = 2.5L x 1.2M = ?
?mols/10.0L = ??
To find the molarity of the KNO3 solution after dilution, we can use the equation:
M1V1 = M2V2
Where:
M1 = initial molarity
V1 = initial volume
M2 = final molarity
V2 = final volume
In this case:
M1 = 1.2 M (initial molarity)
V1 = 2.5 L (initial volume)
V2 = 10.0 L (final volume)
1. Rearrange the equation to solve for M2:
M2 = (M1 x V1) / V2
2. Substitute the given values into the equation:
M2 = (1.2 M x 2.5 L) / 10.0 L
3. Calculate the final molarity:
M2 = (3.0 mol/L) / (10.0 L)
M2 = 0.3 M
Therefore, the molarity of the KNO3 solution after dilution would be 0.3 M.