calculate the current in the secondary coil when the current in the primary coil is 0.50 A. there are 200 turns in the primary coil and 3000 turns on the secondary. the input voltage is 55 v
I pri/I sec= Nsec/Npri=Vsec/Vpri
you can use that.
I sec=.50(200/3000) amps
To calculate the current in the secondary coil when the current in the primary coil is 0.50 A, you need to use the turns ratio and the principle of transformer operation.
The turns ratio (Np/Ns) is the ratio of the number of turns in the primary coil (Np) to the number of turns in the secondary coil (Ns). In this case, Np = 200 and Ns = 3000, so the turns ratio can be calculated as:
Turns Ratio = Np/Ns = 200/3000 = 1/15
According to the principle of transformer operation, the ratio of voltages in a transformer is equal to the turns ratio. So, the voltage across the secondary coil (Vs) can be calculated using the following equation:
Vs/Vp = Ns/Np
where Vp is the voltage across the primary coil. In this case, Vp = 55 V, so we can rearrange the equation to solve for Vs:
Vs = Vp * (Ns/Np)
Substituting the given values, we have:
Vs = 55 V * (3000/200) = 825 V
Now, we can use Ohm's Law to calculate the current (Is) in the secondary coil. Ohm's Law states that current is equal to voltage divided by resistance. In this case, we assume the secondary coil has a load connected to it, so there is resistance.
Is = Vs / Rs
Since the load resistance (Rs) is not given, we cannot calculate the exact current in the secondary coil without knowing the load. However, you can use this formula with the given voltage across the secondary coil (Vs) and the load resistance (Rs) to find the current (Is) in the secondary coil.