Two parallel plate capacitor of capacitant, two microfarad &three microfarad are connec ted in parallel and d combination is 50V direct current. Draw d circuit diagram of arrangement and determine d following (i)charge on either plate of each capacity. (ii)p.d across d each capacitor (iii)energy of the combined
To draw the circuit diagram, we can represent the parallel combination of two capacitors as follows:
_______________________________
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| |
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| C1 C2 |
| -------||--------||-------- |
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|________________|
In this diagram, C1 represents the capacitor with a capacitance of 2 microfarads, and C2 represents the capacitor with a capacitance of 3 microfarads. The || symbols indicate that the capacitors are connected in parallel.
(i) To find the charge on either plate of each capacitor, we can use the formula Q = CV, where Q represents the charge, C represents the capacitance, and V represents the voltage.
For C1:
Q1 = (2 microfarads) * (50V) = 100 microcoulombs
For C2:
Q2 = (3 microfarads) * (50V) = 150 microcoulombs
(ii) The potential difference (p.d.) across each capacitor in a parallel combination is the same and equals the applied voltage, which is 50V in this case. So the p.d. across each capacitor is 50V.
(iii) To find the energy of the combined capacitors, we can use the formula W = (1/2)CV², where W represents the energy, C represents the capacitance, and V represents the voltage.
For the combined capacitors:
C_total = C1 + C2 = 2 microfarads + 3 microfarads = 5 microfarads
W_total = (1/2) * (5 microfarads) * (50V)² = 6.25 millijoules
Therefore, the energy of the combined capacitors is 6.25 millijoules.